If my math skills were less rusty…
… I probably would have known that there would be some neat and simple way of turning a quadratic curve into a cubic one. It seems that for any quadratic bezier of the form [P1, C, P2] (where C is the control point) you can form an equivalent cubic bezier with [P1, (C*2/3 + P1 * 1/3), (C*2/3 + P2 * 1/3), P2]. Isn’t that interesting!
